5x-18x^(1/2)-9=0

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Solution for 5x-18x^(1/2)-9=0 equation:


D( x )

x < 0

x < 0

x in <0:+oo)

5*x-(18*x^(1/2))-9 = 0

5*x-18*x^(1/2)-9 = 0

t_1 = x^(1/2)

5*t_1^2-18*t_1^1-9 = 0

5*t_1^2-18*t_1-9 = 0

DELTA = (-18)^2-(-9*4*5)

DELTA = 504

DELTA > 0

t_1 = (504^(1/2)+18)/(2*5) or t_1 = (18-504^(1/2))/(2*5)

t_1 = (6*14^(1/2)+18)/10 or t_1 = (18-6*14^(1/2))/10

t_1 = (18-6*14^(1/2))/10

x^(1/2)-((18-6*14^(1/2))/10) = 0

1*x^(1/2) = (18-6*14^(1/2))/10 // : 1

x^(1/2) = (18-6*14^(1/2))/10

( (18-6*14^(1/2))/10 < 0 i 1/2 in (0:1) ) => x należy do O

t_1 = (6*14^(1/2)+18)/10

x^(1/2)-((6*14^(1/2)+18)/10) = 0

1*x^(1/2) = (6*14^(1/2)+18)/10 // : 1

x^(1/2) = (6*14^(1/2)+18)/10

x^(1/2) = (6*14^(1/2)+18)/10 // ^ 2

x = ((6*14^(1/2)+18)^2)/100

x = ((6*14^(1/2)+18)^2)/100

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